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please mark me as brainliest
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(I) p (x) = x^2-4x+3
If p(0), p(1),p(2),p(3),
case 1. p(0)= (0)^2-4(0)+3
= 3
case 2. p(1)= (1)^2-4(1)+3
= 1-4+3
=0
case 3. p(2)= (2)^2-4(2)+3
=4 -8+3
= -1
case 4. p(3)= (3)^2-4(3)+3
=9-12+3
=0
(II) p(x)= x^2-9
If p(-3)= (-3)^2-9
=9-9=0
And If p(3)= (3)^2-9
=9-9=0
Hence verified!
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