Question

please slove the problem from matrix i want quickly

Answer 1

Answer:

Step-by-step explanation:

take first matrix

and multiply by k

then compare matrix by original ka matrix

Answer 2

Answer:

k, a and b are -6, -4 and -9 respectively.

Step-by-step explanation:

Given,

$A=\begin{bmatrix}0 & 2 \\ 3 & -4\end{bmatrix}$

$\because kA= k\begin{bmatrix}0 & 2 \\ 3 & -4\end{bmatrix}=\begin{bmatrix}0 & 2k \\ 3k & -4k\end{bmatrix}$

According to the question,

$kA=\begin{bmatrix}0 & 3a \\ 2b & 24\end{bmatrix}$

$\implies \begin{bmatrix}0 & 2k \\ 3k & -4k\end{bmatrix}=\begin{bmatrix}0 & 3a\\ 2b & 24\end{bmatrix}$

By comparing,

2k = 3a, 3k = 2b and -4k = 24

If -4k = 24 ⇒ k = -6,

2(-6) = 3a

-12 = 3a

⇒ a = -4

3(-6) = 2b

-18 = 2b

⇒ b = -9