Question

Please slove
the question ​

Answer 1

Answer:

x = 1

Step-by-step explanation:

$\frac{ 17(2-x) }{ 1-7x } + \frac{ 5(x+12) }{ 7x-1 } =8$

multiplying both sides of equation by $7x - 1$, the least common multiple of $1-7x \: and \: 7x-1$.

$(\frac{ 17(2-x) }{ 1-7x } + \frac{ 5(x+12) }{ 7x-1 })(7x-1) =8(7x-1)$

$-17\left(2-x\right)+5\left(x+12\right)=8\left(7x-1\right)$

$-34+17x+5x+60=8\left(7x-1\right)$

$-34+22x+60=8\left(7x-1\right)$

$26+22x=8\left(7x-1\right)$

$26+22x=56x-8$

$26+22x-56x=-8$

$-34x=-8-26$

$-34x=-34$

$x=\frac{-34}{-34}$

$x=1$