Math, asked by aharicharanreddy27, 1 day ago

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Answered by gvishnuvardhanreddy9
0

Answer:

8/25, 12/25 ,0, 1, 3/25

Step-by-step explanation:

i) number of favourable cases= (60,70) and (70,80) as milk bill lies between 60 and 80. Hence number of favourable houses

= 3 + 5 .

= 8.

total number of cases= total number of houses= 25.

P(bill is between 60 and 80) = number of favourable cases/ total cases=8/25

ii) number of favourable cases= (40,50) , (50,60) , (60,70) .

= 4 + 5 +3

= 12.

(60,70) is also included because range (60,70) is actually (60,69)

this follows for all ranges for example (40,50) is actually range (40,49) because 50 is included in (50,60).

total number of cases=25.

P(houses paying at most 69 Rs for bill)= 12/25

iii) In given data, no house is paying milk bill above 100rupees ,so no.of possible outcomes=0 and total no.of outcomes= 25

probability= 0/25=0.

iv) In given data, all houses are paying milk bill between the range of 40-100 ,so no.of possible outcomes=25 and total no.of outcomes= 25

probability= 25/25=1.

v) no.of possible outcomes=3

total no.of outcomes= 25

probability= 3/25

Hope it helps

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