Question

Please slove this for me .​

Answer 1

Given equation

=> 27x[1 + (r/100)]⁷ = 64x[1 + (r/100)]⁴

=> x[1 + (r/100)]⁴{27[1 + (r/100)]³ - 64} = 0

=> Either x = 0

Or [1 + (r/100)]⁴ = 0

Or {27[1 + (r/100)]³ - 64} = 0

=> Either x = 0

Or r = (-100)

Or [1 + (r/100)]³ = (4/3)³

=> Either x = 0

Or r = (-100)

Or r = (100/3)

This is the required solution

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Answer 2

Answer:

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