Math, asked by letsbegin1, 2 months ago

please slove this problem​

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Answers

Answered by Anonymous
6

{\large{\pmb{\sf{\bigstar \:{\underline{Required \; Solution...}}}}}}

Question:

{\small{\underline{\boxed{\sf{\bull \: \dfrac{-2}{3} \times \dfrac{1}{5} - \dfrac{1}{5} \times \dfrac{3}{4} + \dfrac{1}{5}}}}}}

Full Solution:

{\small{\underline{\boxed{\sf{\bull \dfrac{-2}{3} \times \dfrac{1}{5} - \dfrac{1}{5} \times \dfrac{3}{4} + \dfrac{1}{5}}}}}} \\ \\ :\implies \sf \dfrac{-2}{3} \times \dfrac{1}{5} - \dfrac{1}{5} \times \dfrac{3}{4} + \dfrac{1}{5} \\ \\ \longrightarrow \sf We \: have \: to \: use \: BODMAS \\ \\ \longrightarrow \sf BODMAS \: stands \: for \: the \: following \\ \\ \leadsto \sf B \: denotes \: Brackets \\ \\ \leadsto \sf O \: denotes \: Of \\ \\ \leadsto \sf D \: denotes \: Division \\ \\ \leadsto \sf M \: denotes \: Multiplication \\ \\ \leadsto \sf A \: denotes \: Additional \\ \\ \leadsto \sf S \: denotes \: Subtraction \\ \\ \longrightarrow \sf Solving \: the \: Question \\ \\ :\implies \sf \dfrac{-2}{3} \times \dfrac{1}{5} - \dfrac{1}{5} \times \dfrac{3}{4} + \dfrac{1}{5} \\ \\ :\implies \sf \dfrac{-2}{15} - \dfrac{-3}{20} + \dfrac{1}{5} \\ \\ \longrightarrow \sf Now \: taking \: LCM \\ \\ :\implies \sf \dfrac{(4 \times -2) - (3 \times -3) + (12 \times 1)}{60} \\ \\ :\implies \sf \dfrac{(-8) - (-9) + 12}{60} \\ \\ :\implies \sf \dfrac{-8+9+12}{60} \\ \\ :\implies \sf \dfrac{-8+21}{60} \\ \\ :\implies \sf \dfrac{13}{60} \\ \\ {\small{\underline{\boxed{\sf{Solution \: = \dfrac{13}{60}}}}}}

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