Question

Please slove this question​

Answer 1

Step-by-step explanation:

Let the four consecutive term :-

(a-3d), (a-d), (a+d), (a+3d)

----------------------------------------

Sum :-

=> a-3d + a-d + a+d + a+3d = 32

=> 4a = 32

=> a = 8 (first term)

----------------------------------------

Ratio :-

(a-3d) (a+3d) 7

=> ----------------- = ----

(a-d) (a+d) 15

Put the value of a = 8

64 + 24d - 24d - 9d² 7

=> --------------------------- = -----

64 + 8d - 8d - d² 15

=> 960 - 135d² = 448 - 7d²

=> 128d² = 512

=> d² = 4

=> d = 2 (difference)

----------------------------------------

1st term = a-3d => 8 - 6 => 2

2nd term = a-d => 8 - 2 => 6

3rd term = a + d => 8 + 2 => 10

4th term = a +3d => 8 + 6 => 14

So the terms are 2, 6, 10 and 14