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Given :-
AB = CF
EF = BD
∠AFE = ∠DBC
To Prove :-
ΔAFE ≅ ΔCBD
Proof :-
ΔAFE and ΔCBD
AB = CF [Given] ← (1)
∠AFE = ∠DBC [Given] ← (2)
EF = BD [Given]
BF = BF [Common]
Add BF to each sides AB and CF [ ∵ AB = CF]
AB + BF = BF + CF
AF = BC ← (3)
∴ ΔAFE ≅ ΔCBD [ SAS Congruence Rule ]
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