Question

Please slove this question quickly.

Answer 1

Answer:

Step-by-step explanation:

{i^18 + (1/i)^25}^3=2(1-i)

{(i^2)^9+(1/i^24)(1/i)}^3=2(1-i)

as we know that

i^2=-1

{(-1)^9+(1/(i^2)^12)(1/i)}^3=2(1-i)

{-1+(1/1)(1/i)}^3=2(1-i)

apply the cubic formula

(a+b)^3=a^3+b^3+3ab(a+b)

-1^3+1/i^3+3(-1)(1/i)(-1+1/i)=2(1-i)

-1+1/i^3+3/i-3/i^2=2(1-i)

-1+1/-i+3