Question

please so it I will mark you as brainliest ​

Answer 1

Answer:

Amount = 45254, CI = 11254

Step-by-step explanation:

P = 34000, Time = 3 years, R = 10%

A = P(1 + r/100)^n

  = 34000(1 + 10/100)³

  = 34000(110/100)³

  = 45254

C.I = A - P

    = 45254 - 34000

    = 11254

Hope it helps!

Answer 2

$QUESTION$

Find the amount and compound interest on Rs. 34000 for 3 years at the rate of 10 percent per annum.

$SOLUTION$

$GIVEN$

PRINCIPAL= 34000 ;

TIME = 3 years ;

RATE = 10% p.a.

$FORMULA$

$A=P(1+\frac{R}{100})^n$

$=>A = P(1+\frac{R}{100})^3$

$=> A = 34000( 1 +\frac{10}{100})^3$

$=> A = 34000( 1 +\frac{1}{10})^3$

$=> A = 34000(\frac{10+1}{10})^3$

$=> A = 34000(\frac{11}{10})^3$

$=> A = 34000×\frac{1331}{1000}$

$=> A = 34× 1331$

$=> A = 45254$

$THEREFORE$

AMOUNT = Rs.45254

COMPOUND INTEREST = Amount – Principal

= 45254 – 34000

= Rs. 11254

AMOUNT = Rs. 45254

COMPOUND INTEREST = Rs. 11254