Question

please solbe this problem .​

Answer 1

Answer:

the solution is written on the attachment.

Answer 2

★ Question ★

Evaluate $\large=\frac{cos81°+cos72°}{sin18°+cos81°}$

$\rule{300}2$

★ Solution ★

→ cos 72°= cos(90°-18°)=sin18°

$\rightarrow \frac{cos81°+cos72°}{sin18°+cos81°} \\ \rightarrow \frac{cos81°+sin18°}{sin18°+cos81°} = 1$