Math, asked by vishwajeetsingh27, 4 months ago

please sole it no spam

Attachments:

Answers

Answered by Anonymous
2

Answer:

Step-by-step explanation:

m=cosA-sinA and n=cosA+sinA

m²=cos²A+sin²Am²=1-2sinAcosA

n²=cos²A+sin²Am²=1+2sinAcosA

m²-n²=-4sinAcosA

m²+n²=2

m²-n² / m²-n²= -2sinAcosA

*******************************

Now 2 / tanA + cot A

2/ (sinA/cosA+cosA/sinA)

=2/ {(sin²A+cos²A)/sinAcosA)

=2sinAcosA/1

=2sinAcosA

So m²-n² / m²-n²= -2sinAcosA=-2/tanA +cotA

Answered by Anonymous
7

Answer:

OOO HLO ME BHAI NHI HU ... FOR UR KIND INFORMATION

Attachments:
Similar questions