Question

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Answer 1

$\huge{\underline{\underline{.........Answer..........}}}$

$\huge{\underline{Given:-}}$

a = 10 m/s².

Initial velocity = u.

$\huge{\underline{Explanation:-}}$

By using the nth second distance formula

${S_n = u + \frac{1}{2} a (2n - 1)}$

• Case-1

In 1st second

${S_n = u + \frac{1}{2} a (2n - 1)}$

${S_1 = u + \frac{1}{2} a (2 - 1)}$

${S_1 = u + \frac{1}{2} a }$

$\huge{\boxed{\boxed{S_1 = u + \frac{1}{2} a}}}$

• Case-2

${S_n = u + \frac{1}{2} a (2n - 1)}$

${S_2 = u + \frac{1}{2} a (2 \times 2 - 1)}$

$\huge{\boxed{\boxed{S_2 = u + \frac{1}{2} a \times 3}}}$

as,

${S_1 = (u + \frac{1}{2}a) }$

Substituting the values in ${S_2}$

It becomes

${S_2 = 3 S_1}$

This is the relation between the distances travelled in 1st and 2nd second of the journey.

$\huge{\boxed{\boxed{S_2 = 3S_1}}}$

Answer 2

Answer:

hey mate here is your answer

Explanation:

s1=3s2

Hope you will understand and it will help you