Please solv questions no .10
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Extend the line BR to join DC.
therefore BC is a transversal.
Angle ABR = Angle OCD ( alternate interior angle )
Angle OCD = 45°
In ∆OCD,
Angle ( OCD + ODC + COD ) = 180° ( A.S.P)
45° + 105° + ODC = 180°
ODC = 180° - 150°
ODC = 30°
therefore BC is a transversal.
Angle ABR = Angle OCD ( alternate interior angle )
Angle OCD = 45°
In ∆OCD,
Angle ( OCD + ODC + COD ) = 180° ( A.S.P)
45° + 105° + ODC = 180°
ODC = 180° - 150°
ODC = 30°
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