please solve 1)i).Answer with proper explanation will be marked brainliest.
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The other diagonal is also 10 cm.
Because it is a property of rhombus that when all sides of rhombus are equal,the diagonals bisect each other and hence they are equal
Because it is a property of rhombus that when all sides of rhombus are equal,the diagonals bisect each other and hence they are equal
xyz75:
answer is 24 cm
diagonals of rectangle are equal nd not rhombus
ok,i will check for it..sorry for giving wrong answer..
it's ok
thanks for trying
Answered by
1
Let the diagonals AC and BD intersect each other at O, where AC = 16 cm and let BD = x
We know that the diagonals of a rhombus are perpendicular bisectors of each other.
∴ ∆AOB is a right angle triangle, in which OB=BD ÷ 2 = x ÷ 2 and OA = AC ÷2=10/2=5cm
Now, AB= OA2 + OB2…by pythagoras theorem
∴ 102 = x/(2)2+52
ie. 100 − 25=x2/4
75*4=x2
∴ x2=300
We know that the diagonals of a rhombus are perpendicular bisectors of each other.
∴ ∆AOB is a right angle triangle, in which OB=BD ÷ 2 = x ÷ 2 and OA = AC ÷2=10/2=5cm
Now, AB= OA2 + OB2…by pythagoras theorem
∴ 102 = x/(2)2+52
ie. 100 − 25=x2/4
75*4=x2
∴ x2=300
I think the last part of ur answer is wrong and incomplete
but ur logic helped me to solve the problem and get the answer
So I shall mark ur answer brainliest
welcome
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