please solve 12 n 13th questions!! fast
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Hey there !!!!!!!
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12) a,b,c are in A.P
2b = a+c
b= a+c/2---Equation 1
A B C are said to be in GP if
B=√AC
here A= 3^a B=3^b C=3^c
A*C = 3^a*3^c
AC= 3^(a+c)
Applying square root on both sides
√AC= √3^(a+c)
√AC= 3^(a+c)/2
But from equation 1 a+c/2 = b
√AC= 3^b = B
B=√AC
So, 3^a 3^b 3^c are in A.P
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
13) a,b,c are in A.P
2b = a+c
b= a+c/2---Equation 1
A B C are said to be in GP if
B=√AC
here A= 10^ax+10 B=10^bx+10 C=10^cx+10
A*C = 10^ax+10*10^cx+10
AC= 10^(ax+10+cx+10)= 10^( 20+(a+c)x )
AC=10^( 20+(a+c)x )
Applying square root on both sides
√AC=√10^( 20+(a+c)x )
√AC=10^( (20+(a+c)x) /2)
√AC=10^( 20/2+(a+c)x /2)
From equation 1 a+c/2 = b
√AC=10^( 10+(b)x ) = B
B=√AC
So 10^ax+10 10^bx+10 10^cx+10 are in G.P
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope this helped you.....................
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
12) a,b,c are in A.P
2b = a+c
b= a+c/2---Equation 1
A B C are said to be in GP if
B=√AC
here A= 3^a B=3^b C=3^c
A*C = 3^a*3^c
AC= 3^(a+c)
Applying square root on both sides
√AC= √3^(a+c)
√AC= 3^(a+c)/2
But from equation 1 a+c/2 = b
√AC= 3^b = B
B=√AC
So, 3^a 3^b 3^c are in A.P
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
13) a,b,c are in A.P
2b = a+c
b= a+c/2---Equation 1
A B C are said to be in GP if
B=√AC
here A= 10^ax+10 B=10^bx+10 C=10^cx+10
A*C = 10^ax+10*10^cx+10
AC= 10^(ax+10+cx+10)= 10^( 20+(a+c)x )
AC=10^( 20+(a+c)x )
Applying square root on both sides
√AC=√10^( 20+(a+c)x )
√AC=10^( (20+(a+c)x) /2)
√AC=10^( 20/2+(a+c)x /2)
From equation 1 a+c/2 = b
√AC=10^( 10+(b)x ) = B
B=√AC
So 10^ax+10 10^bx+10 10^cx+10 are in G.P
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope this helped you.....................
Anonymous:
thanks a lotttt!!!!☺
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