Please solve 12 the one attachment is below with diagram and question
Answers
Answer:
Area of the shaded portion :
There are two rectangles and a square in this shaded portion. I have enclosed a diagram so that you can understand easily.
Length and breadth of rectangle ABCD are 50 m and 5 m respectively.
Area of rectangle ABCD = L × B
= 50 × 5
= 250 sq m
Length and breadth of the rectangle EFGH are 35 m and 5 m respectively.
Area of rectangle EFGH = 35 × 5
= 175 sq m
Length of each side of the square IJKL is 5 m.
Area of square = 5 × 5
= 25 sq m
Now, Area of the shaded portion = (Area of rectangle ABCD + Area of rectangle EFGH) - Area of square IJKL
= (250 sq m + 175 sq m) - 25 sq m
= 425 sq m - 25 sq m
= 400 sq m
So, the area of the shaded portion is 400 sq m.
Answer.
Answer:
Step-by-step explanation:
Given: breadth of both path= 4m
length of one path=45m
length if second path=38m
area of whole field= l x b
= 45 x 38
=1680 sq.m
area of path 1 = 45 x 4
= 180 sq.m
area of path 2 = 38 x 4
= 152 sq.m
area of both path= 180+152
=232 sq.m
width of each path is 4 m.Therefore the square formed in the intersection of paths is a square with each side 4 m.
area of common block = 4 x 4
=16 sq.m
We have added it twice because it is common in both paths. So,we will subtract it once.
⇒ 232 - 16
= 216 sq.m
Cost for graveling 1 sq.m = Rs. 5.60
Therefore, cost for graveling 213 sq.m area = 216 x 5.60
= Rs. 1209.6 [Answer]