Physics, asked by parveen845ydv, 9 months ago

please solve ..............​

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Answered by sakthikeerthimvm
0

sorry i dont know

mark me BRAINLIEST

Answered by Anonymous
1

Height of object = 1 cm

U = - 15 cm

f = - 10 cm

Size of image =?

V =?

Nature =?

By mirror formula

 \frac{1}{f}  =  \frac{1}{v }  +  \frac{1}{u}  \\  \frac{1}{ - 10 }  =  \frac{1}{v}   +  \frac{1}{( - 15)}  \\  \frac{1}{ - 10}  +  \frac{1}{15 }  =  \frac{1}{v}  \\   \frac{ - 1}{30 }  =  \frac{1}{v} \\ v =  - 30

Nature :Negative sign shows that the image is formed front of the mirror. And the image is real and inverted.

 \frac{height \: of \: image}{height \: of \: object}  =  -  \frac{v}{u}  \\ height \: of \: image \:  =  \frac { - v}{u}  \times height \: of \: object \\ height \: of \: image \:  =   \frac{    - ( - 30)}{  - 15}  \times 1 \\ height \: of \: image \: =  - 2

Thus the size of image is 2 cm.

thus the image is real and inverted

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