Question

please solve 15th and 17th in notebook
Not irrelevant answers please

Answer 1

here is ur answer...

hope this helps!!!!

Answer 2

4x2 -3x - 1
4x2 -4x + x -1
4x ( x-1) + 1 (x - 1)
x = 1 or x = -1/4

Taking positive x = 1
So 4*(1)2 -3(1) -(1)
4-3-1
0
So the following equations has equal root

Now ...
Quadratic polynomial

So let a and b are the roots of the equations

So.

equation = 4x2 -3x -1
Sum = coefficient of x / coefficient of x2
In the equation
acc to ax2 + bx +c
a = 4
b = -3
c = -1
So = Sum = (a+b)= (-3)/ 4 = -3/4
Now product = ab = constant term / coefficient of x2
= -1 / 4

So the required polynomial

putting the value

= x2 - (a+b)x + ab = 0
Put the value

x2 - (-3/4)x + (-1/4) =0
x2 + (3/4)x - 1/4 =0
x2 + 3x -4/4 = 0
x2 + 3x -4 = 0*4
x2 +3x -4 = 0