Question

please solve 17 no.

Answer 1

angle GCH=60 equal to angle EAG
angle AGH=180-(GCH +GHC) [angle sum property ]
now, GHC=DHF (V. O. A)
and GCH we have found
so, AGH=180-(60+50)
180-110=70

Answer 2

Given figure EF||BC,and CD is transversal.So,angle DHF= angleGHC = 50 degree(vertically opposite angles)

Now, given that AB||CD and EF || BC.
Hence, EBCH is a parallelogram. And opposite angles of parallelogram are equal. So angleGHC = angle EBC=50 degree
By angle sum property in triangle ABC
60+50+ACB = 180
110+ACB=180
ACB=180-110
ACB= 70°

Since EF || BC
AngleAEG=angle ABC= 50
(corresponding angles)
Similarly,angle AGE = AngleACB=70°
Since EF is a line
AGE+AGH=180°
Angle AGH=180-70
=110
Angle AGE =Angle CGH=70

By angle sum property in triangleCGH

CGH+GCH+CHG =180
70+50+GCH=180
120+GCH=180
GCH=180-120
GCH=60

I hope you understand