Question

please solve 18 number

Answer 1

hey
as we know co interior angles is 180 degree
so BEF+DFE=180
DIVIDE BY 2
IT IS GIVEN HALF EG AND FG ARE BISECTOR SO
GEF+EFG=90
NOW IN TRIANGLE EFG
GEF+EFG+EGF=180(ASP)
90+EGF=180
SO EGF=90
H.P.

Answer 2

here ,

m£BEF + m£DFE =180° -------- (1) consecutive interior angels are supplementary


also
m£BEF = m £BEG + m£GEF

but £BEG = £GEF

therefore ,

m£BEF = m £GEF + m£GEF

m£BEF = 2 m £GEF --------( 2 )

and

m£DFE = m £GFE + m£DFG

but £GFE = £DFG

therefore ,

m£DFE= m £GFE+ m£GFE

m£BEF = 2 m £GFE -------(3)

putting the values of 2 and 3 in 1 we get


2 m £GEF + 2 m £GFE = 180°

2 ( m £GEF + m £GFE ) = 180

( m £GEF + m £GFE ) = 90 -------- (4)


now in triangle EFG

m£EGF + m £GEF + m £GFE = 180


m£EGF + 90 = 180 ------ from 4

m£EGF = 180 - 90

m£EGF = 90