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i). V1 = IR
10V = I × 5 Ohm
I = 2A
ii). The same current will run through R also because the combination is in Series.
iii). V2 = IR
6V = 2A × R
R = 3 Ohm
iv). V = V1 + V2
V = (10 + 6) V
V = 16 V
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