Question

please solve 1st b part and 2nd questions

Answer 1

1.b) Here is your answer
$area = \frac{a + b}{2} \times h$
$\frac{10 + 12}{2} \times 5$
$= 55 {cm}^{2}$

2.
Draw a line BC parallel to AD
Draw a perpendicular line BE on DF
ABCD is a parallelogram.
BC=AD=25cm
CD=AB=60cm
CF=77-CD=17cm

For Δ BCF
perimeter of triangle=(25+26+17)/2
=68/2=34
By Heron's Formula of triangle=√s(s-a)(s-b)(s-c)
=√34(34-25)(34-26)(34-17)
=204cm²

Now area of ΔBCF=1/2xbase x height
=1/2 BExCF204cm²
=1/2x BEx17BE
=408/17
=24cm

Area of Trapezium =1/2(AB+DF)xBE
=1/2(60+77)x24
=1644cm²

Hope this answer helped you..