Question

please solve 1st question ​

Answer 1

Answer:

$x^{5} - a ^{2} x ^{3} + 2x + a - 3 \\ \: if \: (x - a)is \: the \: factor \: of \: above \: \\ \\ then \: put \: \\ x - a = 0 \\ x = a(put \: this \: is \: above \: polynomial) \\ \\ (a)^{5} - a^{2} (a)^{3} + 2a + a - 3 = 0 \\ a^{5} - a ^{5} + 3a - 3 = 0\\ 3a - 3 = 0 \\ 3a = 3 \\ a = 3 \div 3 \\ a = 1 \\ \\ this \: is \: your \: answer \: \\ please \: mark \: me \: as \: brainlist \:$

Answer 2

Answer:

1

• Step-by-step explanation:
• Given,f(x)=x⁵-a²x³+2x+a-3
• g(x)=x-a=0,x=a put x value in f(x)
• f(a)= a⁵-a²a³+2a+a-3=0
• a⁵-a⁵+3a-3=0
• 3(a-1)=0
• a-1=0
• a= 1
• The value of a is 1

I HOPE MY SOLUTION IS CLEAR ✌️