please solve 2, 4 bitttt
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kindly refer to attachment for answer of second question.
4))
2^x + 2^(8 - x) = 40
2^x + 2^8 / 2^x - 40 = 0
(2^x)^2 - 40(2^x) + 256 = 0
(2^x - 32)(2^x - 8) = 0
2^x = 32 or 2^x = 8
x = 5 or x = 3
therefore corresponding values of y=3,y=5
x=5,y=3 or x=3,y=5.
4))
2^x + 2^(8 - x) = 40
2^x + 2^8 / 2^x - 40 = 0
(2^x)^2 - 40(2^x) + 256 = 0
(2^x - 32)(2^x - 8) = 0
2^x = 32 or 2^x = 8
x = 5 or x = 3
therefore corresponding values of y=3,y=5
x=5,y=3 or x=3,y=5.
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basasriramamurthy26:
krishithaa I posted bitt
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yaaa
hmmm
Beye Timor I had exam
rishitha I posted bitt
rishitha once post bitt again
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krishitha is right sharanya
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