Question

please solve 22 23 24

Answer 1

this is the first part of ques no.22

Answer 2

$(x + \frac{1 }{x} ) = 6$
given right
${(x + \frac{1}{x} )}^{2} = {6}^{2} \\ {x}^{2} + { \frac{1}{ {x}^{2} } } + 2 \times \ \: x\times \frac{1}{x} = 36$
${x}^{2} + \frac{1}{ {x}^{2} } + 2 = 36 \\ {x}^{2} + \frac{1}{ {x}^{2} } = 34 \\ {x}^{2} + \frac{1}{ {x}^{2} } - 2 = 34 - 2$
${x }^{2} + \frac{1}{ {x}^{2} } - 2 \times x \times \frac{1}{x} = 32 \\ {(x - \frac{1}{x } )}^{2} = { \sqrt{32 } }^{2} \\ x - \frac{1}{x} = \sqrt{32}$
$x - \frac{1}{x} = \sqrt{16 \times 2 } \\ x - \frac{1}{x} = 4 \sqrt{2}$
second part u will get it by multiplying the given and the current answer
final answer for second part $144\sqrt{2}$