Please solve 22,23 and 24 ...
you will get extra points for that...
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22) TSA -CSA of 2 hemisphere +csa of cylinder
- (2)(22/7)(12)(12) + 2(22/7)(12)(108-36)
-2(22/7)(12) (12 + 72)
-6336cm²
cost - 6336 ( 70/100) rupee
ans - 4435.2 rupee
- (2)(22/7)(12)(12) + 2(22/7)(12)(108-36)
-2(22/7)(12) (12 + 72)
-6336cm²
cost - 6336 ( 70/100) rupee
ans - 4435.2 rupee
RJRishabh:
23rd and 24th
just consider p as any prime no like 2 and apply the same method given in ncert and apply this (p² divides a²then p² divides a also.) and if any question arises then I can give you proper solution. .
24) speed be x. distance is given. increase speed x + that increased no. time given y hrs less. speed=distance/time and time = distance /speed equation goes like this. 300/x - 300/x +that no. =y hrs. and this quadratic equation you can solve my your self
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