Math, asked by riharnitja, 1 year ago

Please solve 26

Please won 20 points

Attachments:

kanikachhabra: the length of rectangle is greater than the length of side of square by 3 cm? the picture is not clear.

waRRi0r: ans should be 34cm option D

Answers

Answered by patrajyotishpbu8xx

Answer:

Step-by-step explanation:

26 cm

waRRi0r: i am from India

waRRi0r: and you ?

riharnitja: same as you

riharnitja: from which state

waRRi0r: hahaha state doesn't matter i prefer to be indian as i lived in many states cannot name one

waRRi0r: anyways as long as u are indian it would be easier for me to help you with your question

waRRi0r: somehow i cannot get the answer box on your posted question. so please suggest me a way to communicate you with the details

riharnitja: say one state

waRRi0r: on this chatbox we cannot send attachments

waRRi0r: ok i belong from UP, right now in Delhi but i live in maharastra

Answered by vksundariob

Answer:

Step-by-step explanation:

Let the side of the square be x cm

Area of the square = x^2

Length of the rectangle is 5 cm more than the side of the square and breadth of the rectangle is 3 less than the side of the square.

Then length = x + 5 cm

Breadth = x - 3 cm

Area of rectangle = (x+5) (x-3) sq. cm.

But area of sq and rectangle are same.

Hence, x^2= (x+5) (x-3)

Solving this we get x= 7.5cm

Then length = 7.5+5= 12.5cm

Breadth= 7.5-3= 4.5 cm

Then perimeter of the rectangle

= 2(l +b) cm

= 2(12.5+4.5) = 34 cm

riharnitja: I cannot understand

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