Question

please solve 26th one

Answer 1

${x}^{3} + 4 {x}^{2} - 5 {x}^{2} - 20x + 6x + 24 \\ \\ {x}^{2} (x + 4) - 5x(x + 4) + 6(x + 4) \\ \\ (x + 4)( {x}^{2} - 5x + 6) \\ \\ (x + 4)( {x}^{2} - 2x - 3x + 6) \\ \\ (x + 4)(x - 2)(x - 3) \\ so \: other \: zeroes \: are \: (x - 2) \: and \\ (x - 3)$
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