Question

Please solve? ? ????????????

Answer 1

hey friend

here is ur answer

b²-4ac= (-4p)² - 4 x 4 x (p²-q²)
          = 16 p²- 16p²+ 16q²
          = 16q²

x= -b +- √b² - 4ac/2a
  = 4p + 4q/8 , 4p - 4q /8
  = p+q/2 , p-q/2

hope it helps

please mark it as brainliest

Answer 2

4x2-4px+(p+q)(p-q)=0
=4x2-2(p+q)x-2(p-q)x-(p+q)(p-q)=0
=2x(2x-p-q)-(p-q)(2x-p-q)
=(2x-p+q)(2x-p-q)=0
S, its done. 
Remember, x2 means square of x.
Thank me only if you have understood this sum.