Please solve? ? ????????????
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1
hey friend
here is ur answer
b²-4ac= (-4p)² - 4 x 4 x (p²-q²)
= 16 p²- 16p²+ 16q²
= 16q²
x= -b +- √b² - 4ac/2a
= 4p + 4q/8 , 4p - 4q /8
= p+q/2 , p-q/2
hope it helps
please mark it as brainliest
here is ur answer
b²-4ac= (-4p)² - 4 x 4 x (p²-q²)
= 16 p²- 16p²+ 16q²
= 16q²
x= -b +- √b² - 4ac/2a
= 4p + 4q/8 , 4p - 4q /8
= p+q/2 , p-q/2
hope it helps
please mark it as brainliest
Answered by
1
4x2-4px+(p+q)(p-q)=0
=4x2-2(p+q)x-2(p-q)x-(p+q)(p-q)=0
=2x(2x-p-q)-(p-q)(2x-p-q)
=(2x-p+q)(2x-p-q)=0
S, its done.
Remember, x2 means square of x.
Thank me only if you have understood this sum.
=4x2-2(p+q)x-2(p-q)x-(p+q)(p-q)=0
=2x(2x-p-q)-(p-q)(2x-p-q)
=(2x-p+q)(2x-p-q)=0
S, its done.
Remember, x2 means square of x.
Thank me only if you have understood this sum.
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