Question

please solve 2nd subdivision

Answer 1

Answer:

Step-by-step explanation:

(i)

In Right angled triangle AFO

AF² + OF²= OA² .....(1)

Similarly,,

BD² + OD² =OB²   ....(2)

CE² + OE² =OC²  ....(3)

Now (1) +(2) +(3)

AF² + BD² +CE²+OF²+OD²+OE² =OA²+OB²+OC²

⇔ AF² + BD² +CE²=OA²+OB²+OC²-OF²-OD²-OE²

(ii)

AF² + BD² +CE²=OA²+OB²+OC²-OF²-OD²-OE²

⇔AF² + BD² +CE²=(OA²-OE²)+(OB²-OF²)+(OC²-OD²)

⇔AF² + BD² +CE² = AE² +CD² +DF²