Question

please solve (2x+1)²-(3x+2)²=0​

Answer 1

4x^2+1+4x-9x^2-4-12x=0

-5x^2-8x-3=0

5x^2+8x+3=0

5x^2+5x+3x+3=0

5x(x+1)+3(x+1)=0

(5x+3)(x+1)=0

==>>x=-3/5 and x=-1

Answer 2

4x^2 + 4x + 1 - ( 9x^2 + 4 + 12x ) = 0

4x^2 + 4x + 1 - 9x^2 - 4 - 12x = 0

- 5x^2 - 8x - 3 = 0

5x^2 + 8x + 3 = 0

5x^2 + 5x + 3x + 3 = 0

5x( x + 1 ) + 3( x + 1 ) = 0

(x + 1) (5x + 3) = 0

x + 1 = 0 5x + 3 = 0
x = -1 5x = -3
x = -3/5

Thus, x = -1 , -3/5

Hope it helps you..