Please solve 3 and 4 tomorrow is exam. I am in 7 th standard
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hari49:
Please solve with steps in correct correspondence without mistake.
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3)∆PQR is congruence to∆ABC. PQ=AC,AB=QR,angleA=angle Q. By ASA congruence rule both triangles are congruent. 4)∆AOC and∆BOD are congruent. angle AOC=angleBOD, (vertically opposite angles),OC=OD,OA=OB.
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3) in ΔPQR and ΔABC,
PQ = AC (both 9cm)
QR = AB (both 8 cm)
angle Q = angle A (both 85 degree)
thus,
ΔPQR is congruent to ΔABC, by SAS congruence rule.
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4)in triangles COA and BOD,
CO = OD (given mid point)
AO = OB (given mid point)
angle COA = angle BOD(vertically opp.angles)
thus,
ΔCOA is congruent to ΔBOD, by SAS congruence rule.
hope it helps!!!!
PQ = AC (both 9cm)
QR = AB (both 8 cm)
angle Q = angle A (both 85 degree)
thus,
ΔPQR is congruent to ΔABC, by SAS congruence rule.
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4)in triangles COA and BOD,
CO = OD (given mid point)
AO = OB (given mid point)
angle COA = angle BOD(vertically opp.angles)
thus,
ΔCOA is congruent to ΔBOD, by SAS congruence rule.
hope it helps!!!!
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