Question

Please solve................❇️​

Answer 1

Step-by-step explanation:

Considering the distance between parallel sides (h) = 15 m

let one parallel side of the trapezoid be `a` = 10mAnother parallel side be `b` = 25mThe height that is the distance between the parallel sides = 15mArea = [(a+b)/2]h = [(10+25)/2 × 15] m² = [35/2 × 15] m² = [17.5 × 15]m² = 262.5 m²Cost of watering one m² area = Rs 4Cost of watering 262.5 m² area = Rs 1050

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Answer 2

Solution:-

• Please refer to the attachment for figure ✔️

Given:-

• Two parallel sides AB and CD are 10cm and 25cm respectively.
• Perpendicular distance AD is 15cm

To find:-

• Cost of watering @ ₹4/m²
• Area also

Area of Trapezium/Trapezoid is given by:-

$:➝ \frac{1}{2} \times( sum \: of \: parallel \: sides )\: \times height \: {u}^{2}$

Putting the values, we get:-

$: ➝ \frac{1}{2} \times (10 + 15) \times 15 \: {cm}^{2}$

$: ➝ \frac{625}{2} {cm}^{2}$

• Hence area is 624/2 cm²

Now:-

Area of watering @ ₹4/m²:-

$:↝ ₹\frac{625}{2} \times 4$

$: ↝ ₹ 1250$

• Hence cost watering @ ₹4/m² is ₹1250

Hope it helps you ✔️