Question

please solve!!!!!!!!!!!!!​

Answer 1

Answer:

area of parallelogram = area of first triangle +

area of 2nd triangle

area of first triangle equal to

1/2× base× height

1/2×5×2

2cm^2

perimeter of 2nd triangle=4+3+5= 12cm

2S= 12cm

S=12/2= 6cm

area of 2nd triangle= √s(s-a)(s-b)(s-c)

√6(6-4)(6-3)(6-5)

√6×2×3×1

√2×3×2×3

2×3=6cm^2

area of first triangle + area of 2nd triangle=

2+6=8cm^2

area of parallelogram=8cm^2