Question

please solve .........................

Answer 1

hello friend....!!!

Given clues in the question :

1 ) Acceleration = - 6 m/s^2
( here ( - ) sign is taken because it decelerates

2) Time ( T) = 3 seconds

3) Final velocity ( V) = 0 m/s

know, we should calculate the initial velocity and the distance covered

we know that,

v = u + at

implies, 0 = u -6 ( 3 )

implies, u = 18 m/s

therefore the initial velocity is 18m/s

similarly,

we know that S = ut + 1/2 at^2

therefore,

S = 18 x 3 - 1/2 ( 6 ) ( 3 ) ( 3 )

therefore ,

S = 54 - 18

S = 36 m

therefore the distance covered by the car before stopping is 36m

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Hope it is useful...!!