Math, asked by president123362, 3 months ago

please.. solve.. ...​

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Answered by arivumathis2000
0

Answer:

1

Step-by-step explanation:

x=acos^3t ,y=bsin^3t

x/a=acos^3t/a=cos^3t

(x/a)^2/3=(cos^3t)^2/3=cos^2t

y/b=bsin^3t/b=sin^3t

(y/b)^2/3=(sin^3t)^2/3=sin^2t

(x/a)^2/3 +(y/b)^2/3=cos^2t +sin^2t=1

Answered by riza7715
5

Answer:

If x = a cos^3 theta and y = b sin^3 theta then prove that (x/a)^2/3 + (y/a)^2/3

Ans ) I have got the solution but the only problem is that instead of (y/a)^2/3 it's written = (y/b)^2/3

Therefore, 1 is also added ..

Check whether the given attachment is correct with ur answer

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