Question

please solve 4 question fast and do not send wrong

Answer 1

Ans 1 (i) Square 
           (ii) Square

Answer 2

Hey consider the rhombus ABCD,

Given that One of the diagonal say AC is equal to sides.

So AB=BC=CD=AD=AC.

Now, We see that AC divides the rhombus into two triangles namely ∆ABC, ∆ADC

Now consider the angles of rhombus

A = BAC + DAC.

C = DCA + BCA.

B= B

D=D

Now consider each triangle separately,

In ∆ADC.

We know that AD = DC = CA

thus, it is an equilateral triangle as all sides are equal thus all angles are equal

So D= DAC = DCA = 60°

In ∆ABC.

We know that AB = BC = CA

thus, it is an equilateral triangle as all sides are equal thus all angles are equal

So B= BAC = BCA = 60°

Finally we found all angles of rhombus.

1) A = BAC + DAC = 60+60=120°

2) B =60°

3) C = DCA + BCA = 60+60=120°

4) D =60°.