Chemistry, asked by juhithakkar, 1 year ago

please solve 49 number
i will mark brainlist

Attachments:

Answers

Answered by Navpreet449
2
Hey mate..
Here is your answer

Its answer is one..

As Heat at constant volume is 0.075 calories..

As it is absorbed 1g in 1° Celsius temperature at constant volume .

Hence one mole os gram is 40(0.075) which is equal to 3 cal..
Here Cp -Cv is equal to R
and Cp is equal to 5..

So,
Then Cp-Cv is equal to 5 /3 which is equal to approximately 1....

Hope it will help you my friend

juhithakkar: how 5/3 please explain
Navpreet449: Because Cp-Cv is equal to R
Navpreet449: Here Cp is equal to 5
Navpreet449: and Cp/ Cv is 5/3
Navpreet449: Hope you got it
juhithakkar: ok
juhithakkar: but how you find t p is equal to 5
juhithakkar: cp
Answered by madhura41
2
Heya ✌✌
Here is u r Ans ➡

✨Specific heat of gas at constant volume = 0.075 calg^ -1C°

⭐0.075 cal is absorbed by 1 g of it for 1° rise in temperature at constant volume

So, Total Heat Absorbed by 1 g Mole of The Gas is

40 ( 0.075) = 3cal

Since, Cp - Cv = R ... or Cp = 5
Cp / Cv = 5 / 3

And Hence The Gas is Monatomic .

Ans ➡ (a) one

⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐

Hope This Helps u ☺.


juhithakkar: how 5/3 please explain
madhura41: .............Specific Heat Capacities of Air. The nominal values used for air ........ The ratio CP / CV

It turns out that the ratio of the specific heats is an important number. The symbol we use for the ratio is γ. For a monatomic ideal gas we have:

γ = CP / CV = [5R/2] / [3R/2] = 5/3
Similar questions