please solve 49 number
i will mark brainlist
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Hey mate..
Here is your answer
Its answer is one..
As Heat at constant volume is 0.075 calories..
As it is absorbed 1g in 1° Celsius temperature at constant volume .
Hence one mole os gram is 40(0.075) which is equal to 3 cal..
Here Cp -Cv is equal to R
and Cp is equal to 5..
So,
Then Cp-Cv is equal to 5 /3 which is equal to approximately 1....
Hope it will help you my friend
Here is your answer
Its answer is one..
As Heat at constant volume is 0.075 calories..
As it is absorbed 1g in 1° Celsius temperature at constant volume .
Hence one mole os gram is 40(0.075) which is equal to 3 cal..
Here Cp -Cv is equal to R
and Cp is equal to 5..
So,
Then Cp-Cv is equal to 5 /3 which is equal to approximately 1....
Hope it will help you my friend
juhithakkar:
how 5/3 please explain
Answered by
2
Heya ✌✌
Here is u r Ans ➡
✨Specific heat of gas at constant volume = 0.075 calg^ -1C°
⭐0.075 cal is absorbed by 1 g of it for 1° rise in temperature at constant volume
So, Total Heat Absorbed by 1 g Mole of The Gas is
40 ( 0.075) = 3cal
Since, Cp - Cv = R ... or Cp = 5
Cp / Cv = 5 / 3
And Hence The Gas is Monatomic .
Ans ➡ (a) one
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Hope This Helps u ☺.
Here is u r Ans ➡
✨Specific heat of gas at constant volume = 0.075 calg^ -1C°
⭐0.075 cal is absorbed by 1 g of it for 1° rise in temperature at constant volume
So, Total Heat Absorbed by 1 g Mole of The Gas is
40 ( 0.075) = 3cal
Since, Cp - Cv = R ... or Cp = 5
Cp / Cv = 5 / 3
And Hence The Gas is Monatomic .
Ans ➡ (a) one
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
Hope This Helps u ☺.
It turns out that the ratio of the specific heats is an important number. The symbol we use for the ratio is γ. For a monatomic ideal gas we have:
γ = CP / CV = [5R/2] / [3R/2] = 5/3
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