please solve 4th ques.
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Answered by
1
A+B+C=180
Sin A+B/2=Sin (90_C/2)
Sin A+B/2=cosC/2
Hence prooved
Sin A+B/2=Sin (90_C/2)
Sin A+B/2=cosC/2
Hence prooved
Answered by
1
a+b+c=180°
a+b=180°-c
a+b/2=180°-c/2=90°-b/2
taking sine of both sides
sin(a+b/2)=sin(90°-b/2)=cos b/2
hence proved
second question same as first
a+b=180°-c
a+b/2=180°-c/2=90°-b/2
taking sine of both sides
sin(a+b/2)=sin(90°-b/2)=cos b/2
hence proved
second question same as first
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