please solve 5 and 6
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5.a = 5, d = 11-5
d = 6
nth term = 301
a +(n-1)d = 301
5+(n-1)6 =301
5+ 6n-6 = 301
-1+6n = 301
6n = 301+1
6n = 302
n = 302/6 (Divide by 2 )
n = 151/3
so,151/3 is not a term of the given list of number.
6.Given that the 17th term of an A.P exceeds its 10th term by 7 .
d = ?
⇒a+16d = 1+9d+7
⇒16d-9d = 7
⇒7d = 7
⇒d = 7/7 = 1 .
Therefore , common difference = 1 .
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