Question

Please solve 5 and 6 . I need your help.​

Answer 1

5) 3(1)^2-1

=2

n=1

first term=2

3(2)^2-2

=10-2=8

8

3(9)-3

=24

3(16)-4

44-24

2,10,24,44,70

10-2=24-10=44-24=70-44

8=14=20=26

first term=2

common difference=8,8+6,14+6,20+6

means =10-2,24-10,44-24,70-44

it will get=8,14,20,26

nth term=n+n+6+(n+6)+6+n+6+12