Please solve 5 and 6 . I need your help.
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5) 3(1)^2-1
=2
n=1
first term=2
3(2)^2-2
=10-2=8
8
3(9)-3
=24
3(16)-4
44-24
2,10,24,44,70
10-2=24-10=44-24=70-44
8=14=20=26
first term=2
common difference=8,8+6,14+6,20+6
means =10-2,24-10,44-24,70-44
it will get=8,14,20,26
nth term=n+n+6+(n+6)+6+n+6+12
=2
n=1
first term=2
3(2)^2-2
=10-2=8
8
3(9)-3
=24
3(16)-4
44-24
2,10,24,44,70
10-2=24-10=44-24=70-44
8=14=20=26
first term=2
common difference=8,8+6,14+6,20+6
means =10-2,24-10,44-24,70-44
it will get=8,14,20,26
nth term=n+n+6+(n+6)+6+n+6+12
Monika37114:
Thanks
wait for 10 min I will send 6th question
hmm
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