please solve 8 and 9
Answers
8) GiveN:
- There are two complementary angles.
- One is 10° less than 3 times the other.
To FinD:
- The measure of these angles?
Step-by-Step Explanation:
Let one of the angles be x.
Then other angle will be 3x - 10°
Complementary angles add upto 90°.
⇒ 3x - 10° + x = 90°
⇒ 4x - 10° = 90°
⇒ 4x = 100°
⇒ x = 100° / 4
⇒ x = 25°
Then, 3x - 10° = 65°
The required angles are 25° and 65° (Answer)
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9) As the two lines intersect each other at O, the vertically opposite angles will be equal in measure. Then,
⇒ Angle DOB = Angle AOC
⇒ 2a - 5° = a + 35°
⇒ 2a - a = 35° + 5°
⇒ a = 40°
Now taking DC straight line. Angle DOA and Angle AOC will add upto 180° because they are in the same staright line.
⇒ Angle AOD + Angle AOC = 180°
⇒ b + a + 35° = 180°
⇒ b + 75° = 180°
⇒ b = 105°
Angle b and Angle c are vertically opposite angles. So, they are equal in measure.
The required values of the angles are:
- a = 40°
- b = 105°
- c = 105°
Answer:
Question 8
Given
- First complementary angle = 10⁰ less than the other
SoluTion
- Let the first angle be y
- second angle = 3y - 10
3y - 10 + y = 90
4y - 10 = 90
4y = 90 + 10
4y = 100⁰
y = 100/4
y = 25⁰
Then the second angle = 3y - 10 =65⁰
Verification
LHS = RHS
Question 9
The two lines are interesting each other at O . Then the measure of vertically opposite angle will be equal.
Angle AOD = Angle AOC = 180⁰
b + a + 35 = 180⁰
b + 75⁰ = 180⁰
b = 180⁰ - 75⁰
b = 105⁰
Angle B and C are vertically opposite angle. So they will equal.
- A = 45⁰
- B = 105⁰
- C = 105⁰