please solve 8 question fast in full steps by picture do not solve or write wrong answer
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1) For ABO,
Diagonals of rectangle bisect each other.
therefore, AO=BO
angle BAO=ABO
By ASP of Triangle,
118+BAO+ABO=180
118+2ABO=180 (ABO=BAO)
2ABO=180-118
2ABO=62
ABO=31
2)For ADO
Angle OAD=angle ADO (AO=DO)
90-BAO=ADO
90-31=ADO
59=ADO
3)For angle OCB
angle DAO=Angle OCB (alternate interior angles)
Angle OCB=59
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Diagonals of rectangle bisect each other.
therefore, AO=BO
angle BAO=ABO
By ASP of Triangle,
118+BAO+ABO=180
118+2ABO=180 (ABO=BAO)
2ABO=180-118
2ABO=62
ABO=31
2)For ADO
Angle OAD=angle ADO (AO=DO)
90-BAO=ADO
90-31=ADO
59=ADO
3)For angle OCB
angle DAO=Angle OCB (alternate interior angles)
Angle OCB=59
Pls mark as brainliest
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Please mark brainliest.
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wizardaditya:
I marked your answerbrainliest
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