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✵ Initially the Height of the Tree =15 m
Now , when it breaks a part of it will remain Perpendicular to the Ground (AB) and remaining part (AD) will make angle of 60°
or we can say ab + ad = 15m
Now, in ∆ABD
=> ab = √3ad^ 2
frome (1) and (2)
ad√3+1^2 = 15m
=> ad = 30^√3+1
= 10.98 ...( take √3 = 1.73)
Frome (1)
ab+10.98 = 15
ab = 40.2m..
so its broken at 4.02m from ground..
i hope it will helpfull,to you gyus..❣️❣️
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