Question

please solve 8th one in this ​

Answer 1

Step-by-step explanation:

$r \: = \: - 2 \div \frac{1}{ \sqrt{2} } = - 2 \sqrt{2} = \frac{ - 4}{ \sqrt{2}} \\ similarly \: \frac{8}{ \sqrt{2} } \div - 2 = \frac{ - 4}{ \sqrt{2} } \\ therefore \: it \: is \: a \: gp \:$