Please solve 8th question fastly
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Then answer is 37/4.
Let me tell you why .
The roots of the polynomial are -3,-1/2.
So the value of p and q are 3,1/2
p^2+q^2
=3^2 +(1/2)^2
=9+1/4
=(36+1)/4
=37/4
How did I find the root ?
Multiply the x^2 coefficient with the constant .
I.e) 2*3=6
Divide that number such that the sum of the terms is the middle term coefficient.
That is , 6=-6*-1. Sum is -6 + -1 = -7.
Now divide those numbers by the x^2 coefficient .
That is , -6/2= -3 and -1/2
Hence the equation is like
: (x-3)(x- 1/2)=0
Or (x-3)(2x-1)=0
Change the sign . That is the value .
That is , 3 and 1/2.
Hope this answer helps you.
Mark me as the Brainliest if I am worth it.
Let me tell you why .
The roots of the polynomial are -3,-1/2.
So the value of p and q are 3,1/2
p^2+q^2
=3^2 +(1/2)^2
=9+1/4
=(36+1)/4
=37/4
How did I find the root ?
Multiply the x^2 coefficient with the constant .
I.e) 2*3=6
Divide that number such that the sum of the terms is the middle term coefficient.
That is , 6=-6*-1. Sum is -6 + -1 = -7.
Now divide those numbers by the x^2 coefficient .
That is , -6/2= -3 and -1/2
Hence the equation is like
: (x-3)(x- 1/2)=0
Or (x-3)(2x-1)=0
Change the sign . That is the value .
That is , 3 and 1/2.
Hope this answer helps you.
Mark me as the Brainliest if I am worth it.
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