Math, asked by AniTheRockBoy, 1 year ago

Please Solve 9th No. Question, Fast..

Attachments:

Answers

Answered by mdkumar591

please mark this as brainliest

Attachments:

AniTheRockBoy: Thank You Very much

mdkumar591: welcome

mdkumar591: can you do one thing please mark this as brainliest

AniTheRockBoy: I don’t know how to mark this brainliests so can you explain me

mdkumar591: mark it as brainliest is written on my answer press that

mdkumar591: but i think until you don't get 2 answers

mdkumar591: you can not mark my answer as brainliest

AniTheRockBoy: Ok then thank You again for that sum

Answered by impushpa10

angel ABD + angel ABC=180°

110°+ angel ABC =180°

angel ABC=180°-110°

angel ABC=70°

angel ABC + angel ACE=180°

angel ACB + 150°=180°

angel = 180°-150°

angel ACB=30°

In ∆ABC,

angel A + angel B + angel C=180°

angel A+70°+30°=180°

angel A+ 100°=180°

angel A =180°-100°

angel A=80°

$hope \: it \: is \: helpful$

$please \: mark \: as \: brainleast$

Previous Question

Next Question