please solve a-b=3,a2+b2=20 ab=?
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Answered by
2
Answer:
Hi,
According to the problem given
,a - b = 3 ---( 1 )
a² + b² = 29----( 2 )
We know that the algebraic identity,
( a - b )² = a² + b² - 2ab3²
= 29 - 2 ab[ From ( 1 ) and ( 2 ) ]
9 = 29 - 2ab2ab
= 29 - 92ab
= 20ab
= 20/2ab
= 10I
hope this helps you.:)
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Answered by
1
Answer:
11/2
Step-by-step explanation:
Use the formula (a-b)^2
(a-b)^2=a^2+b^2-2ab
9=20-2ab
2ab=11
ab=11/2
5.5=ab
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