please solve a soon as possible
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Step-by-step explanation:
BC=12cm
CD=9cm
BD=15cm
DA=17cm
∠ABD=90°
now,
AB=?
Using pythagoras theorem, For ΔABD
h^2=p^2+b^2
17=15+b^2
b^2=2
b=√2
∴AB=√2 cm
now,
Perimeter of trapezium= AB+BC+CD+AD
= √2+12+9+17 =38+√2
Area of trapezium=a+b/2 *h
= 17+√2/2*15
=255+15√2 / 2
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